3745012001 has 2 divisors, whose sum is σ = 3745012002. Its totient is φ = 3745012000.

The previous prime is 3745011973. The next prime is 3745012003. The reversal of 3745012001 is 1002105473.

3745012001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3554544400 + 190467601 = 59620^2 + 13801^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3745012001 is a prime.

It is a super-2 number, since 2×3745012001² = 28050229775268048002, which contains 22 as substring.

Together with 3745012003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3745012003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1872506000 + 1872506001.

It is an arithmetic number, because the mean of its divisors is an integer number (1872506001).

Almost surely, 2^3745012001 is an apocalyptic number.

It is an amenable number.

3745012001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3745012001 is an equidigital number, since it uses as much as digits as its factorization.

3745012001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 3745012001 is about 61196.5031762437. The cubic root of 3745012001 is about 1552.9271085516.

Adding to 3745012001 its reverse (1002105473), we get a palindrome (4747117474).

The spelling of 3745012001 in words is "three billion, seven hundred forty-five million, twelve thousand, one".