Search a number
-
+
38214703 is a prime number
BaseRepresentation
bin1001000111000…
…1110000101111
32122220111201101
42101301300233
534240332303
63443023531
7642551062
oct221616057
978814641
1038214703
111a6312aa
121096aba7
137bc0067
14510a8d9
15354cd1d
hex2471c2f

38214703 has 2 divisors, whose sum is σ = 38214704. Its totient is φ = 38214702.

The previous prime is 38214677. The next prime is 38214727. The reversal of 38214703 is 30741283.

38214703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (30741283) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-38214703 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (38214203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19107351 + 19107352.

It is an arithmetic number, because the mean of its divisors is an integer number (19107352).

Almost surely, 238214703 is an apocalyptic number.

38214703 is a deficient number, since it is larger than the sum of its proper divisors (1).

38214703 is an equidigital number, since it uses as much as digits as its factorization.

38214703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

The square root of 38214703 is about 6181.8041864815. The cubic root of 38214703 is about 336.8295327840.

Adding to 38214703 its reverse (30741283), we get a palindrome (68955986).

The spelling of 38214703 in words is "thirty-eight million, two hundred fourteen thousand, seven hundred three".