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38315541133 is a prime number
BaseRepresentation
bin100011101011110010…
…001100001010001101
310122220021110011100001
4203223302030022031
51111432234304013
625334003004301
72524331504002
oct435362141215
9118807404301
1038315541133
1115282140181
127513969691
1337c80b7a3c
141bd69ad8a9
15ee3ba2ddd
hex8ebc8c28d

38315541133 has 2 divisors, whose sum is σ = 38315541134. Its totient is φ = 38315541132.

The previous prime is 38315541079. The next prime is 38315541149. The reversal of 38315541133 is 33114551383.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30522535849 + 7793005284 = 174707^2 + 88278^2 .

It is a cyclic number.

It is not a de Polignac number, because 38315541133 - 221 = 38313443981 is a prime.

It is a super-2 number, since 2×383155411332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 38315541092 and 38315541101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (38315541833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19157770566 + 19157770567.

It is an arithmetic number, because the mean of its divisors is an integer number (19157770567).

Almost surely, 238315541133 is an apocalyptic number.

It is an amenable number.

38315541133 is a deficient number, since it is larger than the sum of its proper divisors (1).

38315541133 is an equidigital number, since it uses as much as digits as its factorization.

38315541133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 64800, while the sum is 37.

The spelling of 38315541133 in words is "thirty-eight billion, three hundred fifteen million, five hundred forty-one thousand, one hundred thirty-three".