38777440430413 has 2 divisors, whose sum is σ = 38777440430414. Its totient is φ = 38777440430412.

The previous prime is 38777440430347. The next prime is 38777440430419. The reversal of 38777440430413 is 31403404477783.

38777440430413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29830145043204 + 8947295387209 = 5461698^2 + 2991203^2 .

It is a cyclic number.

It is not a de Polignac number, because 38777440430413 - 2¹⁷ = 38777440299341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (38777440430419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19388720215206 + 19388720215207.

It is an arithmetic number, because the mean of its divisors is an integer number (19388720215207).

Almost surely, 2^{38777440430413} is an apocalyptic number.

It is an amenable number.

38777440430413 is a deficient number, since it is larger than the sum of its proper divisors (1).

38777440430413 is an equidigital number, since it uses as much as digits as its factorization.

38777440430413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18966528, while the sum is 55.

The spelling of 38777440430413 in words is "thirty-eight trillion, seven hundred seventy-seven billion, four hundred forty million, four hundred thirty thousand, four hundred thirteen".