Base | Representation |
---|---|
bin | 10001101101001010010100… |
… | …10100011001111001100110 |
3 | 12002212011100211111111121120 |
4 | 20312211022110121321212 |
5 | 20100403114100314230 |
6 | 214450314421554410 |
7 | 11125653463230444 |
oct | 1066451224317146 |
9 | 162764324444546 |
10 | 38935125401190 |
11 | 11451326285967 |
12 | 4449a7a875a06 |
13 | 18957499ab665 |
14 | 988682041b94 |
15 | 477bd2d1c310 |
hex | 23694a519e66 |
38935125401190 has 64 divisors (see below), whose sum is σ = 94032741888000. Its totient is φ = 10317432604160.
The previous prime is 38935125401177. The next prime is 38935125401191. The reversal of 38935125401190 is 9110452153983.
It is a super-2 number, since 2×389351254011902 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (38935125401191) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1838686 + ... + 9013934.
It is an arithmetic number, because the mean of its divisors is an integer number (1469261592000).
Almost surely, 238935125401190 is an apocalyptic number.
38935125401190 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
38935125401190 is an abundant number, since it is smaller than the sum of its proper divisors (55097616486810).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
38935125401190 is a wasteful number, since it uses less digits than its factorization.
38935125401190 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7176397.
The product of its (nonzero) digits is 1166400, while the sum is 51.
The spelling of 38935125401190 in words is "thirty-eight trillion, nine hundred thirty-five billion, one hundred twenty-five million, four hundred one thousand, one hundred ninety".
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