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391112141211221 is a prime number
BaseRepresentation
bin101100011101101101110010…
…0001111101000011001010101
31220021210221210120221001202212
41120323123210033220121111
5402230440131122224341
63503454234235443205
7145244630314502603
oct13073334417503125
91807727716831685
10391112141211221
11103690800494331
1237a481a08b6505
1313a30941674a61
146c81d0027c873
153033acea025eb
hex163b6e43e8655

391112141211221 has 2 divisors, whose sum is σ = 391112141211222. Its totient is φ = 391112141211220.

The previous prime is 391112141211119. The next prime is 391112141211247. The reversal of 391112141211221 is 122112141211193.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 336730941052900 + 54381200158321 = 18350230^2 + 7374361^2 .

It is a cyclic number.

It is not a de Polignac number, because 391112141211221 - 222 = 391112137016917 is a prime.

It is a super-2 number, since 2×3911121412112212 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (391112141217221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 195556070605610 + 195556070605611.

It is an arithmetic number, because the mean of its divisors is an integer number (195556070605611).

Almost surely, 2391112141211221 is an apocalyptic number.

It is an amenable number.

391112141211221 is a deficient number, since it is larger than the sum of its proper divisors (1).

391112141211221 is an equidigital number, since it uses as much as digits as its factorization.

391112141211221 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1728, while the sum is 32.

The spelling of 391112141211221 in words is "three hundred ninety-one trillion, one hundred twelve billion, one hundred forty-one million, two hundred eleven thousand, two hundred twenty-one".