Base | Representation |
---|---|
bin | 111000111101001101011… |
… | …111110000010000010100 |
3 | 111212011202110110020201102 |
4 | 320331031133300100110 |
5 | 1003111400414021104 |
6 | 12154023541045232 |
7 | 552530643524240 |
oct | 70751537602024 |
9 | 14764673406642 |
10 | 3914015376404 |
11 | 1279a19707281 |
12 | 53268b9b6818 |
13 | 225122b4c933 |
14 | d7621839420 |
15 | 6bc2c3dea1e |
hex | 38f4d7f0414 |
3914015376404 has 24 divisors (see below), whose sum is σ = 8288503151040. Its totient is φ = 1578762504576.
The previous prime is 3914015376391. The next prime is 3914015376407. The reversal of 3914015376404 is 4046735104193.
3914015376404 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3914015376407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4111360214 + ... + 4111361165.
It is an arithmetic number, because the mean of its divisors is an integer number (345354297960).
Almost surely, 23914015376404 is an apocalyptic number.
3914015376404 is a gapful number since it is divisible by the number (34) formed by its first and last digit.
It is an amenable number.
3914015376404 is an abundant number, since it is smaller than the sum of its proper divisors (4374487774636).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3914015376404 is a wasteful number, since it uses less digits than its factorization.
3914015376404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8222721407 (or 8222721405 counting only the distinct ones).
The product of its (nonzero) digits is 1088640, while the sum is 47.
The spelling of 3914015376404 in words is "three trillion, nine hundred fourteen billion, fifteen million, three hundred seventy-six thousand, four hundred four".
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