Base | Representation |
---|---|
bin | 1011011010101000101… |
… | …01111000001000001001 |
3 | 1101111111001211111112202 |
4 | 11231110111320020021 |
5 | 22411320300420001 |
6 | 500111141445545 |
7 | 40224331604123 |
oct | 5552425701011 |
9 | 1344431744482 |
10 | 392257045001 |
11 | 14139a96a738 |
12 | 640321108b5 |
13 | 2acb3436473 |
14 | 14db1aca213 |
15 | a30bc7496b |
hex | 5b54578209 |
392257045001 has 2 divisors, whose sum is σ = 392257045002. Its totient is φ = 392257045000.
The previous prime is 392257044983. The next prime is 392257045003. The reversal of 392257045001 is 100540752293.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 390561252601 + 1695792400 = 624949^2 + 41180^2 .
It is a cyclic number.
It is not a de Polignac number, because 392257045001 - 210 = 392257043977 is a prime.
Together with 392257045003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (392257045003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 196128522500 + 196128522501.
It is an arithmetic number, because the mean of its divisors is an integer number (196128522501).
Almost surely, 2392257045001 is an apocalyptic number.
It is an amenable number.
392257045001 is a deficient number, since it is larger than the sum of its proper divisors (1).
392257045001 is an equidigital number, since it uses as much as digits as its factorization.
392257045001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75600, while the sum is 38.
Adding to 392257045001 its reverse (100540752293), we get a palindrome (492797797294).
The spelling of 392257045001 in words is "three hundred ninety-two billion, two hundred fifty-seven million, forty-five thousand, one".
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