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39414301981 = 199198061819
BaseRepresentation
bin100100101101010001…
…101000010100011101
310202201211221222212021
4210231101220110131
51121210030130411
630035013140141
72563503016255
oct445521502435
9122654858767
1039414301981
111579638949a
12777b92a651
1339419236a2
141c9c8a8965
15105a391a71
hex92d46851d

39414301981 has 4 divisors (see below), whose sum is σ = 39612364000. Its totient is φ = 39216239964.

The previous prime is 39414301963. The next prime is 39414302017. The reversal of 39414301981 is 18910341493.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 18910341493 = 171112373029.

It is a cyclic number.

It is not a de Polignac number, because 39414301981 - 217 = 39414170909 is a prime.

It is a super-2 number, since 2×394143019812 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (39414301481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99030711 + ... + 99031108.

It is an arithmetic number, because the mean of its divisors is an integer number (9903091000).

Almost surely, 239414301981 is an apocalyptic number.

It is an amenable number.

39414301981 is a deficient number, since it is larger than the sum of its proper divisors (198062019).

39414301981 is a wasteful number, since it uses less digits than its factorization.

39414301981 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 198062018.

The product of its (nonzero) digits is 93312, while the sum is 43.

The spelling of 39414301981 in words is "thirty-nine billion, four hundred fourteen million, three hundred one thousand, nine hundred eighty-one".

Divisors: 1 199 198061819 39414301981