Base | Representation |
---|---|
bin | 10001111011010001101101… |
… | …11000111111110001010001 |
3 | 12011120112020200122012022120 |
4 | 20331220312320333301101 |
5 | 20131324411433103432 |
6 | 215501205201524453 |
7 | 11206003405552335 |
oct | 1075506670776121 |
9 | 164515220565276 |
10 | 39420130753617 |
11 | 11618a90147739 |
12 | 4507a76043729 |
13 | 18cc3c14356b3 |
14 | 9a3d31a357c5 |
15 | 48561c346c2c |
hex | 23da36e3fc51 |
39420130753617 has 64 divisors (see below), whose sum is σ = 58101352358400. Its totient is φ = 23662104883200.
The previous prime is 39420130753613. The next prime is 39420130753631. The reversal of 39420130753617 is 71635703102493.
It is not a de Polignac number, because 39420130753617 - 22 = 39420130753613 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 39420130753617.
It is not an unprimeable number, because it can be changed into a prime (39420130753613) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 86648103 + ... + 87101859.
It is an arithmetic number, because the mean of its divisors is an integer number (907833630600).
Almost surely, 239420130753617 is an apocalyptic number.
It is an amenable number.
39420130753617 is a deficient number, since it is larger than the sum of its proper divisors (18681221604783).
39420130753617 is a wasteful number, since it uses less digits than its factorization.
39420130753617 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 454346.
The product of its (nonzero) digits is 2857680, while the sum is 51.
The spelling of 39420130753617 in words is "thirty-nine trillion, four hundred twenty billion, one hundred thirty million, seven hundred fifty-three thousand, six hundred seventeen".
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