Base | Representation |
---|---|
bin | 111001011011000000010… |
… | …110110011100010011111 |
3 | 111222020100000200022222120 |
4 | 321123000112303202133 |
5 | 1004122410314301341 |
6 | 12220434244314023 |
7 | 555042510424035 |
oct | 71330026634237 |
9 | 14866300608876 |
10 | 3946007181471 |
11 | 12915461aa9a3 |
12 | 5389199a2913 |
13 | 228150a7ccc4 |
14 | d8db8608555 |
15 | 6c9a0d0d066 |
hex | 396c05b389f |
3946007181471 has 24 divisors (see below), whose sum is σ = 5449832408880. Its totient is φ = 2539585848960.
The previous prime is 3946007181463. The next prime is 3946007181511. The reversal of 3946007181471 is 1741817006493.
It is not a de Polignac number, because 3946007181471 - 23 = 3946007181463 is a prime.
It is a super-3 number, since 3×39460071814713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3946007181871) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 494100 + ... + 2852393.
It is an arithmetic number, because the mean of its divisors is an integer number (227076350370).
Almost surely, 23946007181471 is an apocalyptic number.
3946007181471 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
3946007181471 is a deficient number, since it is larger than the sum of its proper divisors (1503825227409).
3946007181471 is a wasteful number, since it uses less digits than its factorization.
3946007181471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3346967 (or 3346936 counting only the distinct ones).
The product of its (nonzero) digits is 1016064, while the sum is 51.
The spelling of 3946007181471 in words is "three trillion, nine hundred forty-six billion, seven million, one hundred eighty-one thousand, four hundred seventy-one".
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