Base | Representation |
---|---|
bin | 111001011011011101111… |
… | …111011101111101101111 |
3 | 111222021121200020122111221 |
4 | 321123131333131331233 |
5 | 1004124420110132041 |
6 | 12220555445124211 |
7 | 555061025513155 |
oct | 71333577357557 |
9 | 14867550218457 |
10 | 3946504380271 |
11 | 12917809237a2 |
12 | 538a383b9667 |
13 | 2281cca9408b |
14 | d90246713d5 |
15 | 6c9ce7c12d1 |
hex | 396ddfddf6f |
3946504380271 has 16 divisors (see below), whose sum is σ = 4039314048000. Its totient is φ = 3854974500000.
The previous prime is 3946504380263. The next prime is 3946504380281. The reversal of 3946504380271 is 1720834056493.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 3946504380271 - 23 = 3946504380263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3946504380281) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2286646 + ... + 3622396.
It is an arithmetic number, because the mean of its divisors is an integer number (252457128000).
It is a 1-persistent number, because it is pandigital, but 2⋅3946504380271 = 7893008760542 is not.
Almost surely, 23946504380271 is an apocalyptic number.
3946504380271 is a deficient number, since it is larger than the sum of its proper divisors (92809667729).
3946504380271 is a wasteful number, since it uses less digits than its factorization.
3946504380271 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1336230.
The product of its (nonzero) digits is 4354560, while the sum is 52.
The spelling of 3946504380271 in words is "three trillion, nine hundred forty-six billion, five hundred four million, three hundred eighty thousand, two hundred seventy-one".
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