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39503132897 is a prime number
BaseRepresentation
bin100100110010100100…
…011111100011100001
310202222001010001222012
4210302210133203201
51121400300223042
630051505122305
72565632042444
oct446244374341
9122861101865
1039503132897
1115831541478
1277a5629395
133957156467
141caa5cd65b
15106308be82
hex93291f8e1

39503132897 has 2 divisors, whose sum is σ = 39503132898. Its totient is φ = 39503132896.

The previous prime is 39503132881. The next prime is 39503132899. The reversal of 39503132897 is 79823130593.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39061964881 + 441168016 = 197641^2 + 21004^2 .

It is a cyclic number.

It is not a de Polignac number, because 39503132897 - 24 = 39503132881 is a prime.

It is a super-2 number, since 2×395031328972 (a number of 22 digits) contains 22 as substring.

Together with 39503132899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (39503132899) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19751566448 + 19751566449.

It is an arithmetic number, because the mean of its divisors is an integer number (19751566449).

Almost surely, 239503132897 is an apocalyptic number.

It is an amenable number.

39503132897 is a deficient number, since it is larger than the sum of its proper divisors (1).

39503132897 is an equidigital number, since it uses as much as digits as its factorization.

39503132897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1224720, while the sum is 50.

The spelling of 39503132897 in words is "thirty-nine billion, five hundred three million, one hundred thirty-two thousand, eight hundred ninety-seven".