Search a number
-
+
396667666080 = 25345729314923
BaseRepresentation
bin1011100010110110011…
…11000011111010100000
31101220212110012021020000
411301123033003322200
522444333410303310
6502120540420000
740441536346530
oct5613317037240
91356773167200
10396667666080
11143253613624
1264a63247600
132b53714791a
14152ad7ab4c0
15a4b90aa4c0
hex5c5b3c3ea0

396667666080 has 480 divisors, whose sum is σ = 1605460881024. Its totient is φ = 90351396864.

The previous prime is 396667666069. The next prime is 396667666181. The reversal of 396667666080 is 80666766693.

It is a tau number, because it is divible by the number of its divisors (480).

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a junction number, because it is equal to n+sod(n) for n = 396667665999 and 396667666017.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 26573499 + ... + 26588421.

Almost surely, 2396667666080 is an apocalyptic number.

396667666080 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 396667666080, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (802730440512).

396667666080 is an abundant number, since it is smaller than the sum of its proper divisors (1208793214944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

396667666080 is a wasteful number, since it uses less digits than its factorization.

396667666080 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15250 (or 15233 counting only the distinct ones).

The product of its (nonzero) digits is 70543872, while the sum is 63.

The spelling of 396667666080 in words is "three hundred ninety-six billion, six hundred sixty-seven million, six hundred sixty-six thousand, eighty".