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397440143557 is a prime number
BaseRepresentation
bin1011100100010010100…
…01110101000011000101
31101222212021202012002221
411302021101311003011
523002424134043212
6502325333332341
740466636323462
oct5621121650305
91358767665087
10397440143557
1114360a666366
1265039a970b1
132b62b1b23a2
1415344210669
15a511ce7807
hex5c894750c5

397440143557 has 2 divisors, whose sum is σ = 397440143558. Its totient is φ = 397440143556.

The previous prime is 397440143483. The next prime is 397440143561. The reversal of 397440143557 is 755341044793.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 332174711716 + 65265431841 = 576346^2 + 255471^2 .

It is a cyclic number.

It is not a de Polignac number, because 397440143557 - 215 = 397440110789 is a prime.

It is a super-2 number, since 2×3974401435572 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (397440143587) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 198720071778 + 198720071779.

It is an arithmetic number, because the mean of its divisors is an integer number (198720071779).

Almost surely, 2397440143557 is an apocalyptic number.

It is an amenable number.

397440143557 is a deficient number, since it is larger than the sum of its proper divisors (1).

397440143557 is an equidigital number, since it uses as much as digits as its factorization.

397440143557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6350400, while the sum is 52.

The spelling of 397440143557 in words is "three hundred ninety-seven billion, four hundred forty million, one hundred forty-three thousand, five hundred fifty-seven".