Base | Representation |
---|---|
bin | 1110110101001110… |
… | …0001010010000111 |
3 | 101021110112212112122 |
4 | 3231103201102013 |
5 | 31123204123010 |
6 | 1455021240155 |
7 | 200442431636 |
oct | 35523412207 |
9 | 11243485478 |
10 | 3981317255 |
11 | 1763393643 |
12 | 93140305b |
13 | 4b5aaca36 |
14 | 29aa8d51d |
15 | 1847d4855 |
hex | ed4e1487 |
3981317255 has 4 divisors (see below), whose sum is σ = 4777580712. Its totient is φ = 3185053800.
The previous prime is 3981317237. The next prime is 3981317267. The reversal of 3981317255 is 5527131893.
3981317255 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5527131893 = 43 ⋅128537951.
It is not a de Polignac number, because 3981317255 - 216 = 3981251719 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 398131721 + ... + 398131730.
It is an arithmetic number, because the mean of its divisors is an integer number (1194395178).
Almost surely, 23981317255 is an apocalyptic number.
3981317255 is a deficient number, since it is larger than the sum of its proper divisors (796263457).
3981317255 is an equidigital number, since it uses as much as digits as its factorization.
3981317255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 796263456.
The product of its digits is 226800, while the sum is 44.
The square root of 3981317255 is about 63097.6802663933. The cubic root of 3981317255 is about 1584.9257767921.
The spelling of 3981317255 in words is "three billion, nine hundred eighty-one million, three hundred seventeen thousand, two hundred fifty-five".
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