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3996400000000 = 2105897103
BaseRepresentation
bin111010001001111100000…
…000001001110000000000
3112011001101222122202022211
4322021330000021300000
51010434111400000000
612255530521311504
7561505342341232
oct72117400116000
915131358582284
103996400000000
111300955683361
12546642335594
1322cb22018615
14db5d9190252
156de4ede87ba
hex3a27c009c00

3996400000000 has 396 divisors, whose sum is σ = 10187018221744. Its totient is φ = 1566720000000.

The previous prime is 3996399999983. The next prime is 3996400000003. The reversal of 3996400000000 is 46993.

It is a junction number, because it is equal to n+sod(n) for n = 3996399999899 and 3996399999908.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3996400000003) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 38799999949 + ... + 38800000051.

Almost surely, 23996400000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3996400000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5093509110872).

3996400000000 is an abundant number, since it is smaller than the sum of its proper divisors (6190618221744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3996400000000 is an frugal number, since it uses more digits than its factorization.

3996400000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260 (or 207 counting only the distinct ones).

The product of its (nonzero) digits is 5832, while the sum is 31.

Adding to 3996400000000 its reverse (46993), we get a palindrome (3996400046993).

The spelling of 3996400000000 in words is "three trillion, nine hundred ninety-six billion, four hundred million", and thus it is an aban number.