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39990446413 is a prime number
BaseRepresentation
bin100101001111100111…
…011100100101001101
310211020000002011102221
4211033213130211031
51123400023241123
630212114015341
72614000120531
oct451747344515
9124200064387
1039990446413
1115a61623315
127900877551
133a040b8c58
141d15201bc1
151090c4b25d
hex94f9dc94d

39990446413 has 2 divisors, whose sum is σ = 39990446414. Its totient is φ = 39990446412.

The previous prime is 39990446411. The next prime is 39990446471. The reversal of 39990446413 is 31464409993.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37141769284 + 2848677129 = 192722^2 + 53373^2 .

It is an emirp because it is prime and its reverse (31464409993) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 39990446413 - 21 = 39990446411 is a prime.

It is a super-2 number, since 2×399904464132 (a number of 22 digits) contains 22 as substring.

Together with 39990446411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (39990446411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19995223206 + 19995223207.

It is an arithmetic number, because the mean of its divisors is an integer number (19995223207).

Almost surely, 239990446413 is an apocalyptic number.

It is an amenable number.

39990446413 is a deficient number, since it is larger than the sum of its proper divisors (1).

39990446413 is an equidigital number, since it uses as much as digits as its factorization.

39990446413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2519424, while the sum is 52.

It can be divided in two parts, 3999044641 and 3, that added together give a square (3999044644 = 632382).

The spelling of 39990446413 in words is "thirty-nine billion, nine hundred ninety million, four hundred forty-six thousand, four hundred thirteen".