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39997000049 is a prime number
BaseRepresentation
bin100101010000000000…
…011100100101110001
310211020110102010100012
4211100000130211301
51123403213000144
630212510304305
72614106614406
oct452000344561
9124213363305
1039997000049
1115a6529a146
127902ab8095
133a05571c46
141d1602a2ad
1510915e2e9e
hex95001c971

39997000049 has 2 divisors, whose sum is σ = 39997000050. Its totient is φ = 39997000048.

The previous prime is 39997000039. The next prime is 39997000051. The reversal of 39997000049 is 94000079993.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39994000225 + 2999824 = 199985^2 + 1732^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-39997000049 is a prime.

Together with 39997000051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 39996999970 and 39997000006.

It is not a weakly prime, because it can be changed into another prime (39997000009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19998500024 + 19998500025.

It is an arithmetic number, because the mean of its divisors is an integer number (19998500025).

Almost surely, 239997000049 is an apocalyptic number.

It is an amenable number.

39997000049 is a deficient number, since it is larger than the sum of its proper divisors (1).

39997000049 is an equidigital number, since it uses as much as digits as its factorization.

39997000049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 551124, while the sum is 50.

The spelling of 39997000049 in words is "thirty-nine billion, nine hundred ninety-seven million, forty-nine", and thus it is an aban number.