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40000345231 = 711519485003
BaseRepresentation
bin100101010000001101…
…001101010010001111
310211020200201002001211
4211100031031102033
51123410042021411
630213110115251
72614150216210
oct452015152217
9124220632054
1040000345231
1115a67174460
12790404bb27
133a06173742
141d1665b407
151091a54221
hex95034d48f

40000345231 has 8 divisors (see below), whose sum is σ = 49870560384. Its totient is φ = 31169100120.

The previous prime is 40000345201. The next prime is 40000345237. The reversal of 40000345231 is 13254300004.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 40000345231 - 211 = 40000343183 is a prime.

It is a super-2 number, since 2×400003452312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40000345237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 259742425 + ... + 259742578.

It is an arithmetic number, because the mean of its divisors is an integer number (6233820048).

Almost surely, 240000345231 is an apocalyptic number.

40000345231 is a deficient number, since it is larger than the sum of its proper divisors (9870215153).

40000345231 is a wasteful number, since it uses less digits than its factorization.

40000345231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 519485021.

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 40000345231 its reverse (13254300004), we get a palindrome (53254645235).

The spelling of 40000345231 in words is "forty billion, three hundred forty-five thousand, two hundred thirty-one".

Divisors: 1 7 11 77 519485003 3636395021 5714335033 40000345231