4000251131 has 2 divisors, whose sum is σ = 4000251132. Its totient is φ = 4000251130.

The previous prime is 4000251121. The next prime is 4000251133. The reversal of 4000251131 is 1311520004.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4000251131 is a prime.

It is a super-2 number, since 2×4000251131² = 32004018222133558322, which contains 22 as substring.

Together with 4000251133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4000251133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2000125565 + 2000125566.

It is an arithmetic number, because the mean of its divisors is an integer number (2000125566).

Almost surely, 2^4000251131 is an apocalyptic number.

4000251131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4000251131 is an equidigital number, since it uses as much as digits as its factorization.

4000251131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 4000251131 is about 63247.5385370846. The cubic root of 4000251131 is about 1587.4342717408.

Adding to 4000251131 its reverse (1311520004), we get a palindrome (5311771135).

The spelling of 4000251131 in words is "four billion, two hundred fifty-one thousand, one hundred thirty-one".