4000311243311 has 4 divisors (see below), whose sum is σ = 4000318699272. Its totient is φ = 4000303787352.

The previous prime is 4000311243307. The next prime is 4000311243353. The reversal of 4000311243311 is 1133421130004.

4000311243311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4000311243311 - 2² = 4000311243307 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4000311293311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2855060 + ... + 4018953.

It is an arithmetic number, because the mean of its divisors is an integer number (1000079674818).

Almost surely, 2^{4000311243311} is an apocalyptic number.

4000311243311 is a deficient number, since it is larger than the sum of its proper divisors (7455961).

4000311243311 is an equidigital number, since it uses as much as digits as its factorization.

4000311243311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7455960.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 4000311243311 its reverse (1133421130004), we get a palindrome (5133732373315).

The spelling of 4000311243311 in words is "four trillion, three hundred eleven million, two hundred forty-three thousand, three hundred eleven".