4000401413 has 4 divisors (see below), whose sum is σ = 4093434048. Its totient is φ = 3907368780.

The previous prime is 4000401389. The next prime is 4000401421. The reversal of 4000401413 is 3141040004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4000401413 - 2¹⁴ = 4000385029 is a prime.

It is a super-2 number, since 2×4000401413² = 32006422930264793138, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4000401391 and 4000401400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4000401443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46516253 + ... + 46516338.

It is an arithmetic number, because the mean of its divisors is an integer number (1023358512).

Almost surely, 2^4000401413 is an apocalyptic number.

4000401413 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

4000401413 is a deficient number, since it is larger than the sum of its proper divisors (93032635).

4000401413 is an equidigital number, since it uses as much as digits as its factorization.

4000401413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93032634.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 4000401413 is about 63248.7265721611. The cubic root of 4000401413 is about 1587.4541504769.

Adding to 4000401413 its reverse (3141040004), we get a palindrome (7141441417).

The spelling of 4000401413 in words is "four billion, four hundred one thousand, four hundred thirteen".