Base | Representation |
---|---|
bin | 100101010000100000… |
… | …100111000000101101 |
3 | 10211021001021110220021 |
4 | 211100200213000231 |
5 | 1123412342300331 |
6 | 30213411122141 |
7 | 2614241361421 |
oct | 452040470055 |
9 | 124231243807 |
10 | 40005431341 |
11 | 15a6a028757 |
12 | 79058a3351 |
13 | 3a07234785 |
14 | 1d171c2b81 |
15 | 109220b211 |
hex | 95082702d |
40005431341 has 2 divisors, whose sum is σ = 40005431342. Its totient is φ = 40005431340.
The previous prime is 40005431303. The next prime is 40005431393. The reversal of 40005431341 is 14313450004.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30600504900 + 9404926441 = 174930^2 + 96979^2 .
It is a cyclic number.
It is not a de Polignac number, because 40005431341 - 219 = 40004907053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40005231341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20002715670 + 20002715671.
It is an arithmetic number, because the mean of its divisors is an integer number (20002715671).
Almost surely, 240005431341 is an apocalyptic number.
It is an amenable number.
40005431341 is a deficient number, since it is larger than the sum of its proper divisors (1).
40005431341 is an equidigital number, since it uses as much as digits as its factorization.
40005431341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 40005431341 its reverse (14313450004), we get a palindrome (54318881345).
The spelling of 40005431341 in words is "forty billion, five million, four hundred thirty-one thousand, three hundred forty-one".
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