Base | Representation |
---|---|
bin | 10010001100100010100101… |
… | …00110100000010011011011 |
3 | 12020200020022202101200211011 |
4 | 21012101102212200103123 |
5 | 20221034220043430120 |
6 | 221033505022114351 |
7 | 11266602622021255 |
oct | 1106212246402333 |
9 | 166606282350734 |
10 | 40013301155035 |
11 | 118276003a278a |
12 | 45a2a1971b9b7 |
13 | 194331317cbc0 |
14 | 9c4922c38cd5 |
15 | 495c87809c5a |
hex | 2464529a04db |
40013301155035 has 32 divisors (see below), whose sum is σ = 55169180523072. Its totient is φ = 27597858263040.
The previous prime is 40013301154999. The next prime is 40013301155057. The reversal of 40013301155035 is 53055110331004.
It is not a de Polignac number, because 40013301155035 - 211 = 40013301152987 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40013301154988 and 40013301155006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 138065674 + ... + 138355183.
It is an arithmetic number, because the mean of its divisors is an integer number (1724036891346).
Almost surely, 240013301155035 is an apocalyptic number.
40013301155035 is a deficient number, since it is larger than the sum of its proper divisors (15155879368037).
40013301155035 is a wasteful number, since it uses less digits than its factorization.
40013301155035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 276421023.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 40013301155035 its reverse (53055110331004), we get a palindrome (93068411486039).
The spelling of 40013301155035 in words is "forty trillion, thirteen billion, three hundred one million, one hundred fifty-five thousand, thirty-five".
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