Base | Representation |
---|---|
bin | 10010001100101111011000… |
… | …00001011110001001110101 |
3 | 12020200220001110112112101111 |
4 | 21012113230001132021311 |
5 | 20221142302021333321 |
6 | 221041002355355021 |
7 | 11300235060105640 |
oct | 1106275401361165 |
9 | 166626043475344 |
10 | 40020170105461 |
11 | 1182a505778917 |
12 | 45a4215bb2a71 |
13 | 1943b69290700 |
14 | 9c4db5200a57 |
15 | 49603a8895e1 |
hex | 2465ec05e275 |
40020170105461 has 24 divisors (see below), whose sum is σ = 49841683027584. Its totient is φ = 31462626761280.
The previous prime is 40020170105431. The next prime is 40020170105477. The reversal of 40020170105461 is 16450107102004.
It is not a de Polignac number, because 40020170105461 - 29 = 40020170104949 is a prime.
It is a super-2 number, since 2×400201701054612 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40020170105431) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 107551185 + ... + 107922646.
It is an arithmetic number, because the mean of its divisors is an integer number (2076736792816).
Almost surely, 240020170105461 is an apocalyptic number.
It is an amenable number.
40020170105461 is a deficient number, since it is larger than the sum of its proper divisors (9821512922123).
40020170105461 is a wasteful number, since it uses less digits than its factorization.
40020170105461 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 215474021 (or 215474008 counting only the distinct ones).
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 40020170105461 its reverse (16450107102004), we get a palindrome (56470277207465).
The spelling of 40020170105461 in words is "forty trillion, twenty billion, one hundred seventy million, one hundred five thousand, four hundred sixty-one".
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