400314040211 has 2 divisors, whose sum is σ = 400314040212. Its totient is φ = 400314040210.

The previous prime is 400314040117. The next prime is 400314040213. The reversal of 400314040211 is 112040413004.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 400314040211 - 2³⁸ = 125436133267 is a prime.

It is a super-4 number, since 4×400314040211⁴ (a number of 48 digits) contains 4444 as substring.

Together with 400314040213, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (400314040213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200157020105 + 200157020106.

It is an arithmetic number, because the mean of its divisors is an integer number (200157020106).

Almost surely, 2^400314040211 is an apocalyptic number.

400314040211 is a deficient number, since it is larger than the sum of its proper divisors (1).

400314040211 is an equidigital number, since it uses as much as digits as its factorization.

400314040211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 400314040211 its reverse (112040413004), we get a palindrome (512354453215).

The spelling of 400314040211 in words is "four hundred billion, three hundred fourteen million, forty thousand, two hundred eleven".