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40041131153 = 107374216179
BaseRepresentation
bin100101010010101000…
…110010110010010001
310211100112110012211112
4211102220302302101
51124001012144103
630221124223105
72615153666462
oct452250626221
9124315405745
1040041131153
1115a881a1531
12791583aa95
133a11753c1a
141d1bc36d69
15109540dcd8
hex952a32c91

40041131153 has 4 divisors (see below), whose sum is σ = 40415347440. Its totient is φ = 39666914868.

The previous prime is 40041131099. The next prime is 40041131159. The reversal of 40041131153 is 35113114004.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40041131153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40041131159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187107983 + ... + 187108196.

It is an arithmetic number, because the mean of its divisors is an integer number (10103836860).

Almost surely, 240041131153 is an apocalyptic number.

It is an amenable number.

40041131153 is a deficient number, since it is larger than the sum of its proper divisors (374216287).

40041131153 is a wasteful number, since it uses less digits than its factorization.

40041131153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 374216286.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 40041131153 its reverse (35113114004), we get a palindrome (75154245157).

The spelling of 40041131153 in words is "forty billion, forty-one million, one hundred thirty-one thousand, one hundred fifty-three".

Divisors: 1 107 374216179 40041131153