400433120141 has 4 divisors (see below), whose sum is σ = 400498226784. Its totient is φ = 400368013500.

The previous prime is 400433120137. The next prime is 400433120161. The reversal of 400433120141 is 141021334004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 400433120141 - 2² = 400433120137 is a prime.

It is a super-4 number, since 4×400433120141⁴ (a number of 48 digits) contains 4444 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (400433120161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32544095 + ... + 32556396.

It is an arithmetic number, because the mean of its divisors is an integer number (100124556696).

Almost surely, 2^400433120141 is an apocalyptic number.

It is an amenable number.

400433120141 is a deficient number, since it is larger than the sum of its proper divisors (65106643).

400433120141 is an equidigital number, since it uses as much as digits as its factorization.

400433120141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65106642.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 400433120141 its reverse (141021334004), we get a palindrome (541454454145).

The spelling of 400433120141 in words is "four hundred billion, four hundred thirty-three million, one hundred twenty thousand, one hundred forty-one".