40050111401 has 2 divisors, whose sum is σ = 40050111402. Its totient is φ = 40050111400.

The previous prime is 40050111379. The next prime is 40050111403. The reversal of 40050111401 is 10411105004.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23825466025 + 16224645376 = 154355^2 + 127376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40050111401 is a prime.

It is a super-2 number, since 2×40050111401² (a number of 22 digits) contains 22 as substring.

Together with 40050111403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40050111401.

It is not a weakly prime, because it can be changed into another prime (40050111403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20025055700 + 20025055701.

It is an arithmetic number, because the mean of its divisors is an integer number (20025055701).

Almost surely, 2^40050111401 is an apocalyptic number.

It is an amenable number.

40050111401 is a deficient number, since it is larger than the sum of its proper divisors (1).

40050111401 is an equidigital number, since it uses as much as digits as its factorization.

40050111401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 17.

Adding to 40050111401 its reverse (10411105004), we get a palindrome (50461216405).

The spelling of 40050111401 in words is "forty billion, fifty million, one hundred eleven thousand, four hundred one".