4010012133 has 4 divisors (see below), whose sum is σ = 5346682848. Its totient is φ = 2673341420.

The previous prime is 4010012101. The next prime is 4010012141. The reversal of 4010012133 is 3312100104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4010012133 - 2⁵ = 4010012101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4010011133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668335353 + ... + 668335358.

It is an arithmetic number, because the mean of its divisors is an integer number (1336670712).

Almost surely, 2^4010012133 is an apocalyptic number.

It is an amenable number.

4010012133 is a deficient number, since it is larger than the sum of its proper divisors (1336670715).

4010012133 is a wasteful number, since it uses less digits than its factorization.

4010012133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1336670714.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 4010012133 is about 63324.6565959895. The cubic root of 4010012133 is about 1588.7243876685.

Adding to 4010012133 its reverse (3312100104), we get a palindrome (7322112237).

The spelling of 4010012133 in words is "four billion, ten million, twelve thousand, one hundred thirty-three".