4010312401213 has 4 divisors (see below), whose sum is σ = 4085978672988. Its totient is φ = 3934646129440.

The previous prime is 4010312401169. The next prime is 4010312401217. The reversal of 4010312401213 is 3121042130104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3126520630809 + 883791770404 = 1768197^2 + 940102^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4010312401213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4010312401217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37833135808 + ... + 37833135913.

It is an arithmetic number, because the mean of its divisors is an integer number (1021494668247).

Almost surely, 2^{4010312401213} is an apocalyptic number.

It is an amenable number.

4010312401213 is a deficient number, since it is larger than the sum of its proper divisors (75666271775).

4010312401213 is an equidigital number, since it uses as much as digits as its factorization.

4010312401213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75666271774.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 4010312401213 its reverse (3121042130104), we get a palindrome (7131354531317).

The spelling of 4010312401213 in words is "four trillion, ten billion, three hundred twelve million, four hundred one thousand, two hundred thirteen".