4011130552001 has 2 divisors, whose sum is σ = 4011130552002. Its totient is φ = 4011130552000.

The previous prime is 4011130551941. The next prime is 4011130552003. The reversal of 4011130552001 is 1002550311104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2103834211600 + 1907296340401 = 1450460^2 + 1381049^2 .

It is a cyclic number.

It is not a de Polignac number, because 4011130552001 - 2³⁸ = 3736252645057 is a prime.

Together with 4011130552003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4011130552003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005565276000 + 2005565276001.

It is an arithmetic number, because the mean of its divisors is an integer number (2005565276001).

Almost surely, 2^{4011130552001} is an apocalyptic number.

It is an amenable number.

4011130552001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4011130552001 is an equidigital number, since it uses as much as digits as its factorization.

4011130552001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 4011130552001 its reverse (1002550311104), we get a palindrome (5013680863105).

The spelling of 4011130552001 in words is "four trillion, eleven billion, one hundred thirty million, five hundred fifty-two thousand, one".