40113131 has 2 divisors, whose sum is σ = 40113132. Its totient is φ = 40113130.

The previous prime is 40113053. The next prime is 40113133. The reversal of 40113131 is 13131104.

40113131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40113131 - 2¹⁴ = 40096747 is a prime.

It is a super-2 number, since 2×40113131² = 3218126557246322, which contains 22 as substring.

Together with 40113133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (40113133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20056565 + 20056566.

It is an arithmetic number, because the mean of its divisors is an integer number (20056566).

Almost surely, 2^40113131 is an apocalyptic number.

40113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

40113131 is an equidigital number, since it uses as much as digits as its factorization.

40113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 40113131 is about 6333.4927962381. The cubic root of 40113131 is about 342.3173046637.

Adding to 40113131 its reverse (13131104), we get a palindrome (53244235).

The spelling of 40113131 in words is "forty million, one hundred thirteen thousand, one hundred thirty-one".