4011325345031 has 4 divisors (see below), whose sum is σ = 4011406797912. Its totient is φ = 4011243892152.

The previous prime is 4011325345019. The next prime is 4011325345043. The reversal of 4011325345031 is 1305435231104.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (4011325345019) and next prime (4011325345043).

It is a cyclic number.

It is not a de Polignac number, because 4011325345031 - 2¹⁸ = 4011325082887 is a prime.

It is a super-2 number, since 2×4011325345031² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4011325345051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40652525 + ... + 40751078.

It is an arithmetic number, because the mean of its divisors is an integer number (1002851699478).

Almost surely, 2^{4011325345031} is an apocalyptic number.

4011325345031 is a deficient number, since it is larger than the sum of its proper divisors (81452881).

4011325345031 is an equidigital number, since it uses as much as digits as its factorization.

4011325345031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81452880.

The product of its (nonzero) digits is 21600, while the sum is 32.

The spelling of 4011325345031 in words is "four trillion, eleven billion, three hundred twenty-five million, three hundred forty-five thousand, thirty-one".