40113433431 has 12 divisors (see below), whose sum is σ = 58006960752. Its totient is φ = 26712134496.

The previous prime is 40113433391. The next prime is 40113433433. The reversal of 40113433431 is 13433431104.

It is a de Polignac number, because none of the positive numbers 2^k-40113433431 is a prime.

It is a super-2 number, since 2×40113433431² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40113433395 and 40113433404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40113433433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2504446 + ... + 2520411.

It is an arithmetic number, because the mean of its divisors is an integer number (4833913396).

Almost surely, 2^40113433431 is an apocalyptic number.

40113433431 is a deficient number, since it is larger than the sum of its proper divisors (17893527321).

40113433431 is a wasteful number, since it uses less digits than its factorization.

40113433431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5025750 (or 5025747 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 40113433431 its reverse (13433431104), we get a palindrome (53546864535).

The spelling of 40113433431 in words is "forty billion, one hundred thirteen million, four hundred thirty-three thousand, four hundred thirty-one".