4011401320131 has 4 divisors (see below), whose sum is σ = 5348535093512. Its totient is φ = 2674267546752.

The previous prime is 4011401320123. The next prime is 4011401320177. The reversal of 4011401320131 is 1310231041104.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 4011401320131 - 2³ = 4011401320123 is a prime.

It is a super-2 number, since 2×4011401320131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4011401320098 and 4011401320107.

It is not an unprimeable number, because it can be changed into a prime (4011401320181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668566886686 + ... + 668566886691.

It is an arithmetic number, because the mean of its divisors is an integer number (1337133773378).

Almost surely, 2^{4011401320131} is an apocalyptic number.

4011401320131 is a deficient number, since it is larger than the sum of its proper divisors (1337133773381).

4011401320131 is a wasteful number, since it uses less digits than its factorization.

4011401320131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1337133773380.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 4011401320131 its reverse (1310231041104), we get a palindrome (5321632361235).

It can be divided in two parts, 401140 and 1320131, that added together give a palindrome (1721271).

The spelling of 4011401320131 in words is "four trillion, eleven billion, four hundred one million, three hundred twenty thousand, one hundred thirty-one".