Base | Representation |
---|---|
bin | 111010010111111010110… |
… | …000100010001010010001 |
3 | 112012111011011110200020212 |
4 | 322113322300202022101 |
5 | 1011210332321422001 |
6 | 12310452250213505 |
7 | 562546342164203 |
oct | 72277260421221 |
9 | 15174134420225 |
10 | 4011411514001 |
11 | 1307259249a81 |
12 | 549531724295 |
13 | 231375066398 |
14 | dc220b30773 |
15 | 6e52cc347bb |
hex | 3a5fac22291 |
4011411514001 has 2 divisors, whose sum is σ = 4011411514002. Its totient is φ = 4011411514000.
The previous prime is 4011411513973. The next prime is 4011411514021. The reversal of 4011411514001 is 1004151141104.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2161485099601 + 1849926414400 = 1470199^2 + 1360120^2 .
It is a cyclic number.
It is not a de Polignac number, because 4011411514001 - 218 = 4011411251857 is a prime.
It is not a weakly prime, because it can be changed into another prime (4011411514021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005705757000 + 2005705757001.
It is an arithmetic number, because the mean of its divisors is an integer number (2005705757001).
Almost surely, 24011411514001 is an apocalyptic number.
It is an amenable number.
4011411514001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011411514001 is an equidigital number, since it uses as much as digits as its factorization.
4011411514001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 4011411514001 its reverse (1004151141104), we get a palindrome (5015562655105).
The spelling of 4011411514001 in words is "four trillion, eleven billion, four hundred eleven million, five hundred fourteen thousand, one".
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