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401153253535399 is a prime number
BaseRepresentation
bin101101100110110001100010…
…1001011010110111010100111
31221121100212122222020210000111
41123031203011023112322213
5410034443330401113044
63541103132140353451
7150332236405143511
oct13315430513267247
91847325588223014
10401153253535399
11106902159638a72
1238baa230b45887
13142ab788159c01
14710bcc75a4bb1
153159db3de9b34
hex16cd8c52d6ea7

401153253535399 has 2 divisors, whose sum is σ = 401153253535400. Its totient is φ = 401153253535398.

The previous prime is 401153253535361. The next prime is 401153253535427. The reversal of 401153253535399 is 993535352351104.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401153253535399 - 223 = 401153245146791 is a prime.

It is a super-2 number, since 2×4011532535353992 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401153253535319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200576626767699 + 200576626767700.

It is an arithmetic number, because the mean of its divisors is an integer number (200576626767700).

Almost surely, 2401153253535399 is an apocalyptic number.

401153253535399 is a deficient number, since it is larger than the sum of its proper divisors (1).

401153253535399 is an equidigital number, since it uses as much as digits as its factorization.

401153253535399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32805000, while the sum is 58.

The spelling of 401153253535399 in words is "four hundred one trillion, one hundred fifty-three billion, two hundred fifty-three million, five hundred thirty-five thousand, three hundred ninety-nine".