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401213103 = 3473139091
BaseRepresentation
bin10111111010100…
…000011010101111
31000221221201220120
4113322200122233
51310202304403
6103451220023
712641153334
oct2772403257
91027851816
10401213103
11196524385
12b2447613
1365177805
143b3dc98b
1525352e53
hex17ea06af

401213103 has 16 divisors (see below), whose sum is σ = 548138496. Its totient is φ = 260919360.

The previous prime is 401213083. The next prime is 401213117. The reversal of 401213103 is 301312104.

It is not a de Polignac number, because 401213103 - 212 = 401209007 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401213143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39588 + ... + 48678.

It is an arithmetic number, because the mean of its divisors is an integer number (34258656).

Almost surely, 2401213103 is an apocalyptic number.

401213103 is a deficient number, since it is larger than the sum of its proper divisors (146925393).

401213103 is a wasteful number, since it uses less digits than its factorization.

401213103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9454.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 401213103 is about 20030.3046157566. The cubic root of 401213103 is about 737.5503996199.

Adding to 401213103 its reverse (301312104), we get a palindrome (702525207).

Subtracting from 401213103 its reverse (301312104), we obtain a palindrome (99900999).

The spelling of 401213103 in words is "four hundred one million, two hundred thirteen thousand, one hundred three".

Divisors: 1 3 47 141 313 939 9091 14711 27273 44133 427277 1281831 2845483 8536449 133737701 401213103