Base | Representation |
---|---|
bin | 111010011000101001111… |
… | …100010111001110101111 |
3 | 112012120012100001122121120 |
4 | 322120221330113032233 |
5 | 1011213443001102421 |
6 | 12311103005432023 |
7 | 562605064010541 |
oct | 72305174271657 |
9 | 15176170048546 |
10 | 4012203144111 |
11 | 1307625093438 |
12 | 54971286b613 |
13 | 231470078676 |
14 | dc297d1b691 |
15 | 6e5774a68c6 |
hex | 3a629f173af |
4012203144111 has 64 divisors (see below), whose sum is σ = 5585950702080. Its totient is φ = 2559657000960.
The previous prime is 4012203144097. The next prime is 4012203144133. The reversal of 4012203144111 is 1114413022104.
It is a happy number.
It is not a de Polignac number, because 4012203144111 - 27 = 4012203143983 is a prime.
It is a super-2 number, since 2×40122031441112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4012203144161) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1156586085 + ... + 1156589553.
It is an arithmetic number, because the mean of its divisors is an integer number (87280479720).
Almost surely, 24012203144111 is an apocalyptic number.
4012203144111 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
4012203144111 is a deficient number, since it is larger than the sum of its proper divisors (1573747557969).
4012203144111 is a wasteful number, since it uses less digits than its factorization.
4012203144111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4376.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 4012203144111 its reverse (1114413022104), we get a palindrome (5126616166215).
The spelling of 4012203144111 in words is "four trillion, twelve billion, two hundred three million, one hundred forty-four thousand, one hundred eleven".
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