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4012240213301 = 8191489835211
BaseRepresentation
bin111010011000101100001…
…001110001010100110101
3112012120021220210221222112
4322120230021301110311
51011214031443311201
612311110412140405
7562606024051145
oct72305411612465
915176256727875
104012240213301
111307644002031
12549723167705
132314779571b8
14dc29cc0a925
156e57a87a0bb
hex3a62c271535

4012240213301 has 4 divisors (see below), whose sum is σ = 4012730056704. Its totient is φ = 4011750369900.

The previous prime is 4012240213283. The next prime is 4012240213307. The reversal of 4012240213301 is 1033120422104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4012240213301 - 26 = 4012240213237 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4012240213307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244909415 + ... + 244925796.

It is an arithmetic number, because the mean of its divisors is an integer number (1003182514176).

Almost surely, 24012240213301 is an apocalyptic number.

It is an amenable number.

4012240213301 is a deficient number, since it is larger than the sum of its proper divisors (489843403).

4012240213301 is an equidigital number, since it uses as much as digits as its factorization.

4012240213301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 489843402.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 4012240213301 its reverse (1033120422104), we get a palindrome (5045360635405).

The spelling of 4012240213301 in words is "four trillion, twelve billion, two hundred forty million, two hundred thirteen thousand, three hundred one".

Divisors: 1 8191 489835211 4012240213301