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40122455215 = 58024491043
BaseRepresentation
bin100101010111011111…
…000001010010101111
310211120012110220110211
4211113133001102233
51124132322031330
630233151243251
72620162146043
oct452737012257
9124505426424
1040122455215
111601a0974a7
127938b19527
133a25558b7b
141d28966023
15109c624d2a
hex9577c14af

40122455215 has 4 divisors (see below), whose sum is σ = 48146946264. Its totient is φ = 32097964168.

The previous prime is 40122455209. The next prime is 40122455237. The reversal of 40122455215 is 51255422104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40122455215 - 211 = 40122453167 is a prime.

It is a super-2 number, since 2×401224552152 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4012245517 + ... + 4012245526.

It is an arithmetic number, because the mean of its divisors is an integer number (12036736566).

Almost surely, 240122455215 is an apocalyptic number.

40122455215 is a deficient number, since it is larger than the sum of its proper divisors (8024491049).

40122455215 is an equidigital number, since it uses as much as digits as its factorization.

40122455215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8024491048.

The product of its (nonzero) digits is 16000, while the sum is 31.

Adding to 40122455215 its reverse (51255422104), we get a palindrome (91377877319).

The spelling of 40122455215 in words is "forty billion, one hundred twenty-two million, four hundred fifty-five thousand, two hundred fifteen".

Divisors: 1 5 8024491043 40122455215