Search a number
-
+
401241041303 = 451388907831
BaseRepresentation
bin1011101011010111101…
…01000110100110010111
31102100200011210210121112
411311223311012212113
523033220201310203
6504154432005235
740663061402144
oct5655365064627
91370604723545
10401241041303
11145190120073
126591a99081b
132bab57a22cb
14155c4d373cb
15a68583e6d8
hex5d6bd46997

401241041303 has 4 divisors (see below), whose sum is σ = 401329953648. Its totient is φ = 401152128960.

The previous prime is 401241041269. The next prime is 401241041309. The reversal of 401241041303 is 303140142104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 401241041303 - 210 = 401241040279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401241041309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44449403 + ... + 44458428.

It is an arithmetic number, because the mean of its divisors is an integer number (100332488412).

Almost surely, 2401241041303 is an apocalyptic number.

401241041303 is a deficient number, since it is larger than the sum of its proper divisors (88912345).

401241041303 is an equidigital number, since it uses as much as digits as its factorization.

401241041303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88912344.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 401241041303 its reverse (303140142104), we get a palindrome (704381183407).

The spelling of 401241041303 in words is "four hundred one billion, two hundred forty-one million, forty-one thousand, three hundred three".

Divisors: 1 4513 88907831 401241041303