Base | Representation |
---|---|
bin | 101101100111011010100110… |
… | …1000111000000101100110101 |
3 | 1221121200022021101022012220212 |
4 | 1123032311031013000230311 |
5 | 410042414423430140000 |
6 | 3541211434142035205 |
7 | 150341510524040552 |
oct | 13316651507005465 |
9 | 1847608241265825 |
10 | 401241433443125 |
11 | 106936599921870 |
12 | 39003340278b05 |
13 | 142b6b9bb759c2 |
14 | 7112290879a29 |
15 | 315c32559ec35 |
hex | 16ced4d1c0b35 |
401241433443125 has 40 divisors (see below), whose sum is σ = 552611212906368. Its totient is φ = 288803580480000.
The previous prime is 401241433443119. The next prime is 401241433443223. The reversal of 401241433443125 is 521344334142104.
It is not a de Polignac number, because 401241433443125 - 26 = 401241433443061 is a prime.
It is a super-2 number, since 2×4012414334431252 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 300170189 + ... + 301503938.
Almost surely, 2401241433443125 is an apocalyptic number.
It is an amenable number.
401241433443125 is a deficient number, since it is larger than the sum of its proper divisors (151369779463243).
401241433443125 is an equidigital number, since it uses as much as digits as its factorization.
401241433443125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 601674255 (or 601674240 counting only the distinct ones).
The product of its (nonzero) digits is 552960, while the sum is 41.
Adding to 401241433443125 its reverse (521344334142104), we get a palindrome (922585767585229).
The spelling of 401241433443125 in words is "four hundred one trillion, two hundred forty-one billion, four hundred thirty-three million, four hundred forty-three thousand, one hundred twenty-five".
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