Base | Representation |
---|---|
bin | 101101100111011111000111… |
… | …1000110100011000010010111 |
3 | 1221121201020022012010102011212 |
4 | 1123032332033012203002113 |
5 | 410043044303410134341 |
6 | 3541220120304452035 |
7 | 150342303033103433 |
oct | 13316761706430227 |
9 | 1847636265112155 |
10 | 401251130552471 |
11 | 10693a715668621 |
12 | 390051a791a01b |
13 | 142b7a85b92724 |
14 | 71129306b59c3 |
15 | 315c6e1a7c5eb |
hex | 16cef8f1a3097 |
401251130552471 has 2 divisors, whose sum is σ = 401251130552472. Its totient is φ = 401251130552470.
The previous prime is 401251130552453. The next prime is 401251130552513. The reversal of 401251130552471 is 174255031152104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 401251130552471 - 26 = 401251130552407 is a prime.
It is a super-3 number, since 3×4012511305524713 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (401251130552971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200625565276235 + 200625565276236.
It is an arithmetic number, because the mean of its divisors is an integer number (200625565276236).
Almost surely, 2401251130552471 is an apocalyptic number.
401251130552471 is a deficient number, since it is larger than the sum of its proper divisors (1).
401251130552471 is an equidigital number, since it uses as much as digits as its factorization.
401251130552471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168000, while the sum is 41.
The spelling of 401251130552471 in words is "four hundred one trillion, two hundred fifty-one billion, one hundred thirty million, five hundred fifty-two thousand, four hundred seventy-one".
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