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401251130552471 is a prime number
BaseRepresentation
bin101101100111011111000111…
…1000110100011000010010111
31221121201020022012010102011212
41123032332033012203002113
5410043044303410134341
63541220120304452035
7150342303033103433
oct13316761706430227
91847636265112155
10401251130552471
1110693a715668621
12390051a791a01b
13142b7a85b92724
1471129306b59c3
15315c6e1a7c5eb
hex16cef8f1a3097

401251130552471 has 2 divisors, whose sum is σ = 401251130552472. Its totient is φ = 401251130552470.

The previous prime is 401251130552453. The next prime is 401251130552513. The reversal of 401251130552471 is 174255031152104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 401251130552471 - 26 = 401251130552407 is a prime.

It is a super-3 number, since 3×4012511305524713 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401251130552971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200625565276235 + 200625565276236.

It is an arithmetic number, because the mean of its divisors is an integer number (200625565276236).

Almost surely, 2401251130552471 is an apocalyptic number.

401251130552471 is a deficient number, since it is larger than the sum of its proper divisors (1).

401251130552471 is an equidigital number, since it uses as much as digits as its factorization.

401251130552471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168000, while the sum is 41.

The spelling of 401251130552471 in words is "four hundred one trillion, two hundred fifty-one billion, one hundred thirty million, five hundred fifty-two thousand, four hundred seventy-one".