401251130552407 has 2 divisors, whose sum is σ = 401251130552408. Its totient is φ = 401251130552406.

The previous prime is 401251130552339. The next prime is 401251130552449. The reversal of 401251130552407 is 704255031152104.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401251130552407 - 2³⁹ = 400701374738519 is a prime.

It is a super-2 number, since 2×401251130552407² (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 401251130552407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401251130552807) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200625565276203 + 200625565276204.

It is an arithmetic number, because the mean of its divisors is an integer number (200625565276204).

Almost surely, 2^{401251130552407} is an apocalyptic number.

401251130552407 is a deficient number, since it is larger than the sum of its proper divisors (1).

401251130552407 is an equidigital number, since it uses as much as digits as its factorization.

401251130552407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168000, while the sum is 40.

The spelling of 401251130552407 in words is "four hundred one trillion, two hundred fifty-one billion, one hundred thirty million, five hundred fifty-two thousand, four hundred seven".