Search a number
-
+
401300212140 = 223357321148247
BaseRepresentation
bin1011101011011110101…
…10110100100110101100
31102100211022010222202000
411311233112310212230
523033330323242030
6504204344132300
740664410343652
oct5655726644654
91370738128660
10401300212140
11145210564a93
1265936767090
132bac4b1ba39
14155ccb3add2
15a68ab2b860
hex5d6f5b49ac

401300212140 has 192 divisors, whose sum is σ = 1271616568320. Its totient is φ = 105045050880.

The previous prime is 401300212109. The next prime is 401300212141. The reversal of 401300212140 is 41212003104.

401300212140 is a `hidden beast` number, since 401 + 30 + 0 + 21 + 214 + 0 = 666.

It is a super-2 number, since 2×4013002121402 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (401300212141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8293497 + ... + 8341743.

It is an arithmetic number, because the mean of its divisors is an integer number (6623002960).

Almost surely, 2401300212140 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 401300212140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (635808284160).

401300212140 is an abundant number, since it is smaller than the sum of its proper divisors (870316356180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

401300212140 is a wasteful number, since it uses less digits than its factorization.

401300212140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48549 (or 48541 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 401300212140 its reverse (41212003104), we get a palindrome (442512215244).

The spelling of 401300212140 in words is "four hundred one billion, three hundred million, two hundred twelve thousand, one hundred forty".