4013100211 has 2 divisors, whose sum is σ = 4013100212. Its totient is φ = 4013100210.

The previous prime is 4013100209. The next prime is 4013100227. The reversal of 4013100211 is 1120013104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4013100211 - 2¹ = 4013100209 is a prime.

It is a super-2 number, since 2×4013100211² = 32209946607056489042, which contains 22 as substring.

Together with 4013100209, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 4013100191 and 4013100200.

It is not a weakly prime, because it can be changed into another prime (4013100241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006550105 + 2006550106.

It is an arithmetic number, because the mean of its divisors is an integer number (2006550106).

Almost surely, 2^4013100211 is an apocalyptic number.

4013100211 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013100211 is an equidigital number, since it uses as much as digits as its factorization.

4013100211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 4013100211 is about 63349.0348071697. The cubic root of 4013100211 is about 1589.1321043056.

Adding to 4013100211 its reverse (1120013104), we get a palindrome (5133113315).

The spelling of 4013100211 in words is "four billion, thirteen million, one hundred thousand, two hundred eleven".