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4013111322434 = 22006555661217
BaseRepresentation
bin111010011001100000000…
…100110010011101000010
3112012122112121221220001202
4322121200010302131002
51011222322444304214
612311333051101202
7562636432261004
oct72314004623502
915178477856052
104013111322434
111307a507a1235
12549926a41802
132315862766a6
14dc3427a6374
156e5cc09b6de
hex3a660132742

4013111322434 has 4 divisors (see below), whose sum is σ = 6019666983654. Its totient is φ = 2006555661216.

The previous prime is 4013111322373. The next prime is 4013111322457. The reversal of 4013111322434 is 4342231113104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3791178939025 + 221932383409 = 1947095^2 + 471097^2 .

It is a super-2 number, since 2×40131113224342 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4013111322397 and 4013111322406.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1003277830607 + ... + 1003277830610.

Almost surely, 24013111322434 is an apocalyptic number.

4013111322434 is a deficient number, since it is larger than the sum of its proper divisors (2006555661220).

4013111322434 is a wasteful number, since it uses less digits than its factorization.

4013111322434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2006555661219.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4013111322434 its reverse (4342231113104), we get a palindrome (8355342435538).

The spelling of 4013111322434 in words is "four trillion, thirteen billion, one hundred eleven million, three hundred twenty-two thousand, four hundred thirty-four".

Divisors: 1 2 2006555661217 4013111322434